Concurso de badbeats basado en PokerStove

Como me están friendo a Badbeats últimamente, se me ha ocurrido esto.

Consistiría en un concurso de badbeats que hayais sufrido, basado en los porcentajes de PokerStove, en cualquier calle:pre-flop, flop, turn o river.

Es decir, el que pierda una mano con mayor porcentaje a su favor según PokerStove, gana el concurso.

El premio se decidirá más adelante. Puede ser una caja de pañuelos, o una soga, ya veremos.

Para iniciarlo, pongo esta mano.

Según PokerStove, la probabilidad de ganar la mano después del flop (aunque fue all-in preflop, yo iba viendo las cartas, como es natural, y hemos quedado en que vale cualquier calle) era de 96,263% a favor y 3,737% en contra.



1985CIA: posts the ante 15

josen8: posts small blind 75

Mcguider: posts big blind 150

*** HOLE CARDS ***

Dealt to Mcguider [Qs Qh]

FullGainer: folds

xTrav: folds

breden10: folds

1985CIA: folds

SleeperLX: folds

DUbistICH: folds

josen8: raises 1840 to 1990 and is all-in

Mcguider: calls 1040 and is all-in

Uncalled bet (800) returned to josen8

*** FLOP *** [7c As Qc]

*** TURN *** [7c As Qc] [4d]

*** RIVER *** [7c As Qc 4d] [4h]

*** SHOW DOWN ***

josen8: shows [4c 4s] (four of a kind, Fours)

Mcguider: shows [Qs Qh] (a full house, Queens full of Fours)

FullGainer said, "lol"

josen8 collected 2500 from pot

*** SUMMARY ***

Total pot 2500 | Rake 0

Board [7c As Qc 4d 4h]

Seat 1: SleeperLX folded before Flop (didn't bet)

Seat 2: DUbistICH (button) folded before Flop (didn't bet)

Seat 3: josen8 (small blind) showed [4c 4s] and won (2500) with four of a kind, Fours

Seat 4: Mcguider (big blind) showed [Qs Qh] and lost with a full house, Queens full of Fours

Seat 5: FullGainer folded before Flop (didn't bet)

Seat 6: xTrav folded before Flop (didn't bet)

Seat 8: breden10 folded before Flop (didn't bet)

Seat 9: 1985CIA folded before Flop (didn't bet)

Espero que os animeis.